document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=210350>Question 210350</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An object is moving in a straight line. It initially travels at a speed of 6 meters per second, and it speeds up at a constant acceleration of 4 meters per second each second. The distance d, in meters, that this object travels is given by the equation d = 2t^2 + 6t, where t is in seconds. According to this<BR>\n" );
document.write( "equation, how long will it take the object to travel 108 meters? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158972 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158972\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d = 2t^2 + 6t<BR>\n" );
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document.write( "d = 108<BR>\n" );
document.write( "2t^2 + 6t = 108<BR>\n" );
document.write( "t^2 + 3t - 54 = 0<BR>\n" );
document.write( "(t+9)*(t-6) = 0<BR>\n" );
document.write( "t = 6 seconds (ignore the -9 seconds)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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