document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29041>Question 29041</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2(2x + 1) = x + 15 + 2x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15891 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15891\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2(2x + 1) = x + 15 + 2x<BR>\n" );
document.write( "4x+2 = 15 +(x+2x)<BR>\n" );
document.write( "[expanding on the LHs, that is multiplying every term in the bracket by the 2 outside and on the RHS,using additive commutativity and associativity namely <BR>\n" );
document.write( "x + 15 + 2x= (x+15)+2x = (15+x)+2x = 15 + (x+2x) which amounts to grouping like terms]<BR>\n" );
document.write( "4x+2 = 15+3x<BR>\n" );
document.write( "4x-3x=15-2  (grouping like terms by transferring terms from one side to another side changing sign whenever changing side. ) (or here in other words adding <BR>\n" );
document.write( "(-3x) to both the sides and adding (-2) to both the sides )<BR>\n" );
document.write( "x=13<BR>\n" );
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