document.write( "Question 210049: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling 60mph, Train B traveling at 64mph. Train A passes by the station at 4:15am and train B passes the same station at 4:45am, at what time will the train B catch up to train A? \n" ); document.write( "

Algebra.Com's Answer #158880 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Train A and B are traveling in the same direction on parallel tracks. Train A is traveling 60mph, Train B traveling at 64mph. Train A passes by the station at 4:15am and train B passes the same station at 4:45am, at what time will the train B catch up to train A?
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\n" ); document.write( "from the given information, we know that train B is 30 min, (.5 hrs) behind
\n" ); document.write( " train A, when train A passes the station
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\n" ); document.write( "The distance between the trains at this time: .5 * 64 = 32 mi
\n" ); document.write( ":
\n" ); document.write( "Let t = time required for train B to catch train A
\n" ); document.write( ":
\n" ); document.write( "write a distance equation: Dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "Train B travel dist = Train A travel dist + 32 mi
\n" ); document.write( "64t = 60t + 32
\n" ); document.write( "64t - 60t = 32
\n" ); document.write( "4t = 32
\n" ); document.write( "t = $\"32%2F4\"$
\n" ); document.write( "t = 8 hrs
\n" ); document.write( ":
\n" ); document.write( "4:15 AM + 8:00 = 12:15 pm, B catches A \n" ); document.write( "

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