document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=210231>Question 210231</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the length of the side of a square if the diagonal is 3 ft. longer than a side. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158858 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158858\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the length of the side of a square if the diagonal is 3 ft. longer than a side.<BR>\n" );
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document.write( "Let x = length of the side of a square<BR>\n" );
document.write( "then from Pythagorean theorem we get:<BR>\n" );
document.write( "x^2 + x^2 = x+3<BR>\n" );
document.write( "2x^2 = x+3<BR>\n" );
document.write( "2x^2-x-3 = 0<BR>\n" );
document.write( "(2x-3)(x+1) = 0<BR>\n" );
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document.write( "x = {3/2, -1}<BR>\n" );
document.write( "We can throw out the negative solution leaving:<BR>\n" );
document.write( "x = 3/2 feet (or 1 and a half feet)<BR>\n" );
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