document.write( "Question 210214: Express as a single logarithm.\r
\n" ); document.write( "\n" ); document.write( "logc x + logc y \r
\n" ); document.write( "\n" ); document.write( "A)logc
\n" ); document.write( "B)logc x ∙ logc y
\n" ); document.write( "C)logc xy
\n" ); document.write( "D)logc (x + y)
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Algebra.Com's Answer #158845 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Express as a single logarithm.
\n" ); document.write( "logc x + logc y
\n" ); document.write( "Comment: logs are exponents. You are adding two exponents.
\n" ); document.write( "That implies that you are multiplying.
\n" ); document.write( "Answer: = logc(xy)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "A)logc
\n" ); document.write( "B)logc x ∙ logc y
\n" ); document.write( "C)logc xy
\n" ); document.write( "D)logc (x + y)
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