document.write( "Question 210202: A staff member mixed a 35% solution with a 10% solution. How many liters of each will she need to mix in order to obtain 450 liters of a 20% solution? \n" ); document.write( "
Algebra.Com's Answer #158841 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A staff member mixed a 35% solution with a 10% solution. How many liters of each will she need to mix in order to obtain 450 liters of a 20% solution? \n" ); document.write( "-------------------------- \n" ); document.write( "Equation: \n" ); document.write( "0.35x + 0.10(450-x) = 0.20*450 \n" ); document.write( "-------------------- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "35x + 10(450-x) = 20*450 \n" ); document.write( "35x + 10*450 - 10x = 20*450 \n" ); document.write( "25x = 10*450 \n" ); document.write( "x = 10*18 \n" ); document.write( "x = 180 liters (amt. of 35% solution needed in the mixture) \n" ); document.write( "--- \n" ); document.write( "450-180 = 270 liters (amt. of 10% solution needed in the mixture) \n" ); document.write( "==================================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |