document.write( "Question 210204: Please help me solve this equation: $\"+2x%5E2+=+98+\"$ \r
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Algebra.Com's Answer #158838 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( " $\"2x%5E2=98\"$ Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2=%2898%29%2F%282%29\"$ Divide both sides by $\"2\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2=49\"$ Reduce.\r
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\n" ); document.write( "\n" ); document.write( " $\"x=%22%22%2B-sqrt%2849%29\"$ Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( " $\"x=sqrt%2849%29\"$ or $\"x=-sqrt%2849%29\"$ Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( " $\"x=7\"$ or $\"x=-7\"$ Take the square root of $\"49\"$ to get $\"7\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are $\"x=7\"$ or $\"x=-7\"$ .
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