document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=210198>Question 210198</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An object is launched straight up into the air at an initial velocity of 64 feet per second. It is launched from a height of 6 feet off the ground. Its height H, in feet, at t seconds is given by the equation H = -16t^2 + 64t + 6. Find all times t that the object is at a height of 54 feet off the ground. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158832 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158832\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> H = -16t^2 + 64t + 6 = 54<BR>\n" );
document.write( "-t^2 + 4t - 3 = 0<BR>\n" );
document.write( "-(t-1)*(t-3) = 0<BR>\n" );
document.write( "t = 1 second ascending<BR>\n" );
document.write( "t = 3 seconds descending<BR>\n" );
document.write( " </SPAN>\n" );
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