document.write( "Question 210150: I was working on my Algebra and it came up with a Geometry Problem. Sorry Only thing I know of is that I must do x=3 . After that im lost.\r
\n" ); document.write( "\n" ); document.write( "Heres the Problem.
\n" ); document.write( "Find the length and width of a rectangle which has a perimeter of 24. And the Length is 3 inches greater then the width.
\n" ); document.write( "

Algebra.Com's Answer #158803 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The perimeter P of any rectangle with length L and width W is \"P=2L%2B2W\". Since the rectangle has \"a perimeter of 24\", this means \"P=24\". Plug this in to get \"24=2L%2B2W\". This is our first equation.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Also, since \"the Length is 3 inches greater then the width\", this means that we take the unknown width W and add 3 inches to it to get the length L. Algebraically, we get: \"L=W%2B3\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"24=2L%2B2W\" Start with the first equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"24=2%28W%2B3%29%2B2W\" Plug in \"L=W%2B3\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"24=2W%2B6%2B2W\" Distribute.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"24=4W%2B6\" Combine like terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"24-6=4W\" Subtract \"6\" from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"18=4W\" Combine like terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%2818%29%2F4=W\" Divide both sides by \"4\" to isolate \"W\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"9%2F2=W\" Reduce.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"W=9%2F2\" Rearrange the equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"W=4.5\" Divide\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the width is 4.5 inches.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since the length is \"3 inches greater then the width\", just add 3 to the width to get the length like so: \"L=4.5%2B3=7.5\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=============================================\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the length and width are 7.5 inches and 4.5 inches respectively.
\n" ); document.write( "
\n" );