document.write( "Question 210150: I was working on my Algebra and it came up with a Geometry Problem. Sorry Only thing I know of is that I must do x=3 . After that im lost.\r
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document.write( "Heres the Problem.
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document.write( "Find the length and width of a rectangle which has a perimeter of 24. And the Length is 3 inches greater then the width. \n" );
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Algebra.Com's Answer #158800 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Find the length and width of a rectangle which has a perimeter of 24. And the Length is 3 inches greater then the width. \n" ); document.write( "----------- \n" ); document.write( "Perimeter = 2L + 2W \n" ); document.write( "L = W + 3 (length is 3 more than width) \n" ); document.write( "Sub for L in 1st equation \n" ); document.write( "P = 2(W + 3) + 2W \n" ); document.write( "24 = 2W + 6 + 2W \n" ); document.write( "24 = 4W + 6 \n" ); document.write( "4W = 18 \n" ); document.write( "W = 4.5 inches \n" ); document.write( "L = 7.5 inches \n" ); document.write( " \n" ); document.write( " |