document.write( "Question 210149: Is this correct?
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\n" ); document.write( "x = 25 +-Square root -23i over 6?
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Algebra.Com's Answer #158797 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming you meant to write \"3x%5E2-5x%2B4+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2-5x%2B4=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"3x%5E2-5x%2B4\" is in the form of \"Ax%5E2%2BBx%2BC\" where \"A=3\", \"B=-5\", and \"C=4\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"x\":\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-5%29+%2B-+sqrt%28+%28-5%29%5E2-4%283%29%284%29+%29%29%2F%282%283%29%29\" Plug in \"A=3\", \"B=-5\", and \"C=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+%28-5%29%5E2-4%283%29%284%29+%29%29%2F%282%283%29%29\" Negate \"-5\" to get \"5\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+25-4%283%29%284%29+%29%29%2F%282%283%29%29\" Square \"-5\" to get \"25\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+25-48+%29%29%2F%282%283%29%29\" Multiply \"4%283%29%284%29\" to get \"48\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+-23+%29%29%2F%282%283%29%29\" Subtract \"48\" from \"25\" to get \"-23\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+-23+%29%29%2F%286%29\" Multiply \"2\" and \"3\" to get \"6\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+i%2Asqrt%2823%29%29%2F%286%29\" Simplify the square root \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285%2Bi%2Asqrt%2823%29%29%2F%286%29\" or \"x+=+%285-i%2Asqrt%2823%29%29%2F%286%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x+=+%285%2Bi%2Asqrt%2823%29%29%2F%286%29\" or \"x+=+%285-i%2Asqrt%2823%29%29%2F%286%29\"
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