document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29073>Question 29073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a boat travels 12 miles downstream in 1.5 hours. on the return trip the boat travles the same distance upstream in 2 hours. find the rate of the boat in still water and the rate of the current </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15877 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15877\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the speed of the boat be x<BR>\n" );
document.write( "Let the speed of the current be y\r<BR>\n" );
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document.write( "1.5(x+y)=12---->1.5x+1.5y=12 (1)<BR>\n" );
document.write( "solve for y in there.<BR>\n" );
document.write( "1.5y=12-1.5x<BR>\n" );
document.write( "y=8-x (subsitution)\r<BR>\n" );
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document.write( "second equation:<BR>\n" );
document.write( "2(x-y)=12<BR>\n" );
document.write( "2x-2y=12<BR>\n" );
document.write( "Subsitute for y<BR>\n" );
document.write( "2x-2(8-x)=12<BR>\n" );
document.write( "2x-16+2x=12<BR>\n" );
document.write( "4x=28<BR>\n" );
document.write( "x=7\r<BR>\n" );
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document.write( "y=8-7<BR>\n" );
document.write( "y=1\r<BR>\n" );
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document.write( "Hence, the speed of the boat is 7mph and the speed of the current 1mph.<BR>\n" );
document.write( "Paul.<BR>\n" );
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