document.write( "Question 210066: solve 1=(y+3)(2y-2) \n" ); document.write( "

Algebra.Com's Answer #158757 by Earlsdon(6294) $\"\"$ $\"About$

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Solve for y:
\n" ); document.write( " $\"1+=+%28y%2B3%29%282y-2%29\"$ Perform the indicated multiplication on the right side.
\n" ); document.write( " $\"1+=+2y%5E2%2B4y-6\"$ Subtract 1 from both sides.
\n" ); document.write( " $\"2y%5E2%2B4y-7+=+0\"$ Use the quadratic formula to solve for y: $\"y+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\"$ and here, a = 2, b = 4, and c = -7. Making the appropriate substitutions, we get:
\n" ); document.write( " $\"y+=+%28-4%2B-sqrt%28%28-4%29%5E2-4%282%29%28-7%29%29%29%2F2%282%29\"$ Evaluate.
\n" ); document.write( " $\"y+=+%28-4%2B-sqrt%2816-%28-56%29%29%29%2F4\"$
\n" ); document.write( " $\"y+=+%28-4%2B-sqrt%2872%29%29%2F4\"$
\n" ); document.write( " $\"y+=+%28-4%2B6%2Asqrt%282%29%29%2F4\"$ or $\"y+=+%28-4-6%2Asqrt%282%29%29%2F4\"$
\n" ); document.write( " $\"y+=+-1%2B%283%2F2%29sqrt%282%29\"$ or $\"y+=+-1-%283%2F2%29sqrt%282%29\"$ \n" ); document.write( "

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