document.write( "Question 210011: High concentrations of Carbon Monoxide (CO) can cause coma and possible death. The time required for a person to reach a COHb level capable of causing a coma can be approximated by the quadratic model. T=.0002x^2 - .316x + 127.9, where T is the exposure time in hours necessary to reach this level and 500<= x <=800 is the amount of carbon monoxide present in the air in parts per million (ppm).\r
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document.write( "Estimate the approximate concentration of (CO) necessary to produce a coma in 4 hrs?. \n" );
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Algebra.Com's Answer #158722 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! T=.0002x^2 - .316x + 127.9, where T is the exposure time in hours necessary to reach this level and 500<= x <=800 is the amount of carbon monoxide present in the air in parts per million (ppm). \n" ); document.write( "Estimate the approximate concentration of (CO) necessary to produce a coma in \n" ); document.write( "4 hrs \n" ); document.write( "------------- \n" ); document.write( "4 = 0.0002x^2 - .316x + 127.9 \n" ); document.write( "------------- \n" ); document.write( "0.0002x^2 - .316x + 123.9 = 0 \n" ); document.write( "--- \n" ); document.write( "Solve using the Quadratic Formula: \n" ); document.write( "x = [0.316 +- sqrt(0.316^2 - 4*0.0002*123.9)]/[2(0.0002)] \n" ); document.write( "--- \n" ); document.write( "x = [0.316 +- sqrt(0.0007360]/0.0004 \n" ); document.write( "x = [0.316+-0.027129]/0.0004 \n" ); document.write( "x = 857.82 ppm or x = 722.18 ppm \n" ); document.write( "======================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "Reply to stanbon@comcast.net \n" ); document.write( "=======================================\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |