document.write( "Question 209992: the leght of a rectangle is 5 cm greater than its width. the perimeter is 58 cm. find the dimension of the rectangle \n" ); document.write( "
Algebra.Com's Answer #158691 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W+5 \n" ); document.write( "2L+2W=58 \n" ); document.write( "2(W+5)+2W=58 \n" ); document.write( "2W+10+2W=58 \n" ); document.write( "4W=58-10 \n" ); document.write( "4W=48 \n" ); document.write( "W=48/4 \n" ); document.write( "W=12 cm. \n" ); document.write( "L=12+5=17 cm. \n" ); document.write( "PROOF: \n" ); document.write( "2*17+2*12=58 \n" ); document.write( "34+24=58 \n" ); document.write( "58=58\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |