document.write( "Question 209992: the leght of a rectangle is 5 cm greater than its width. the perimeter is 58 cm. find the dimension of the rectangle \n" ); document.write( "
Algebra.Com's Answer #158691 by checkley77(12844)\"\" \"About 
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L=W+5
\n" ); document.write( "2L+2W=58
\n" ); document.write( "2(W+5)+2W=58
\n" ); document.write( "2W+10+2W=58
\n" ); document.write( "4W=58-10
\n" ); document.write( "4W=48
\n" ); document.write( "W=48/4
\n" ); document.write( "W=12 cm.
\n" ); document.write( "L=12+5=17 cm.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*17+2*12=58
\n" ); document.write( "34+24=58
\n" ); document.write( "58=58\r
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