document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209979>Question 209979</A>: <I><SPAN STYLE=\"word-break: break-all;\"> is there a formula to figure out the sides of a triangle, when the perimeter equals 76 cm. the 2nd side is 2x the 1st side and the 3rd side is 4 cm shorter than the the 2nd side. please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158683 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158683\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Try this:<BR>\n" );
document.write( "The perimeter of a triangle is equal to the sum of the lengths of the three sides, so...<BR>\n" );
document.write( "P = 2x+(2x-4)+(2x-4) Combine the x's.<BR>\n" );
document.write( "P = 6x-8 Substitute P = 76.<BR>\n" );
document.write( "76 = 6x-8 Add 8 to both sides.<BR>\n" );
document.write( "84 = 6x Divide both sides by 6.<BR>\n" );
document.write( "x = 14<BR>\n" );
document.write( "2x = 28<BR>\n" );
document.write( "2x-4 = 24<BR>\n" );
document.write( "The three sides are:<BR>\n" );
document.write( "28cm, 24cm, and 24cm.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );