document.write( "Question 209958This question is from textbook Moving straight ahead Linear RelationShips
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document.write( ": Im totaly lost on my 8th grade math homework. It says *For each equations in Exercises 18-21, give two values for x for which the value of y is negative.*
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document.write( "For 18. y=-2x-5
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document.write( "19. y= -4
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document.write( "20. y=2x-5
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document.write( "21. y=3/2x-1/4 \n" );
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Algebra.Com's Answer #158668 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! 18) \n" ); document.write( "for y to be negative here, any x that is positive will do. Even x=0 would make y negative \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "You could solve it algebraically this way. In order for y to be negative, it must be \"less than 0\" \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "19) y= -4 \n" ); document.write( "This is a horizontal line. So all x, no matter what value has a y = -4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20) \n" ); document.write( " \n" ); document.write( "In this much like 18. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Any x less than 2.5 yields a y that is negative \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "21) \n" ); document.write( " \n" ); document.write( "Same idea here \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Any x less than 1/6 works \n" ); document.write( " |