document.write( "Question 209910: The product of two positive numbers is 1 and their difference is 3/2. Find the larger number. PLEASE explain how to do it??? \n" ); document.write( "
Algebra.Com's Answer #158654 by Earlsdon(6294)\"\" \"About 
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Let a = the larger number and b = the smaller number.
\n" ); document.write( "\"a%2Ab+=+1\" and...
\n" ); document.write( "\"a-b+=+3%2F2\" Rewrite this as \"a+=+b%2B3%2F2\" and substitute into the first equation.
\n" ); document.write( "\"%28b%2B3%2F2%29%2Ab+=+1\" Simplify.
\n" ); document.write( "\"b%5E2%2B%283%2F2%29b+=+1\" Subtract 1 from both sides.
\n" ); document.write( "\"b%5E2%2B%283%2F2%29b-1+=+0\" Multiply through by 2 to clear the fraction.
\n" ); document.write( "\"2b%5E2%2B3b-2+=+0\" Factor this trinomial.
\n" ); document.write( "\"%282b-1%29%28b%2B2%29+=+0\" Apply the zero product rule.
\n" ); document.write( "\"2b-1+=+0\" or \"b%2B2+=+0\" so that...
\n" ); document.write( "\"2b+=+1\" or \"b+=+-2\" Discard the negative solution as the numbers are to be positive.
\n" ); document.write( "\"2b+=+1\" Divide both sides by 2.
\n" ); document.write( "\"b+=+1%2F2\" This is the smaller number.
\n" ); document.write( "\"a+=+b%2B3%2F2\" Substitute b = 1/2.
\n" ); document.write( "\"a+=+1%2F2+%2B+3%2F2\"
\n" ); document.write( "\"highlight%28b+=+2%29\" This is the larger number.
\n" ); document.write( "Check:
\n" ); document.write( "\"a%2Ab+=+%282%29%2A%281%2F2%29\"
\n" ); document.write( "\"a%2Ab+=+1\" and...
\n" ); document.write( "\"a-b+=+2-1%2F2\"
\n" ); document.write( "\"a-b+=+3%2F2\"
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