document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209882>Question 209882</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618250220/algebrahomeworkh>Geometry</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I do not know how to figure out line segments with Algebra. It says to use the Segment Addition Postulate but I do not know what that is.\r<BR>\n" );
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document.write( "31. LM=3x+8<BR>\n" );
document.write( "   MN=2x-5<BR>\n" );
document.write( "   LN=23\r<BR>\n" );
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document.write( "32. LM=7y+9<BR>\n" );
document.write( "    MN=3y+4<BR>\n" );
document.write( "    LN=143 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158652 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158652\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "If B is between A and C, then AB + BC = AC. The converse is also the same. If AB + BC = AC, then B is between A and C.\r<BR>\n" );
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document.write( "So, for your problem 31, presuming that the points are labeled in alphabetical order, you can say:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ (3x + 8) + (2x - 5) = 23\">\r<BR>\n" );
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document.write( "Just solve for <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large x\">.\r<BR>\n" );
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document.write( "Solve the other problem the same way.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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