document.write( "Question 209856: I need help with this problem. The perimeter of a rectangle is 44 inches, and its area is 112 square inches. Find the length and width of the rectangle.
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Algebra.Com's Answer #158631 by checkley77(12844)\"\" \"About 
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2L+2W=44
\n" ); document.write( "LW=112
\n" ); document.write( "L=112/W
\n" ); document.write( "2(112/W)+2W=44
\n" ); document.write( "(224/W)+2W=44
\n" ); document.write( "(224+2W*W)/W=44
\n" ); document.write( "224+2W^2=44*W
\n" ); document.write( "224+2W^2=44W
\n" ); document.write( "2W^2-44W+224=0
\n" ); document.write( "2(W^2-22W+112)=0
\n" ); document.write( "2(W-14)(W-8)=0
\n" ); document.write( "W-14=0
\n" ); document.write( "W=14 ANS. L=112/14=8 ANS.
\n" ); document.write( "W-8=0
\n" ); document.write( "W=8 ANS. L=112/8=14 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "8*14=112
\n" ); document.write( "2*14+2*8=44
\n" ); document.write( "28+16=44
\n" ); document.write( "44=44\r
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