document.write( "Question 29033: Find the real number n so that the given three points are collinear: (6,3), (n,-1), and (-3,-3) \n" ); document.write( "
Algebra.Com's Answer #15862 by Earlsdon(6294)\"\" \"About 
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Here's one approach:\r
\n" ); document.write( "\n" ); document.write( "First, find the slope of the line using two of the known points.
\n" ); document.write( "Then you can use the slope formula\"m+=+%28y2-y1%29%2F%28x2-x1%29\" to find the value of n.\r
\n" ); document.write( "\n" ); document.write( "\"m+=+%28y2-y1%29%2F%28x2-x1%29\" Use the points (6, 3) and (-3, -3) as (x1, y1) and (x2, y2)\r
\n" ); document.write( "\n" ); document.write( "\"m+=+%28-3-3%29%2F%28-3-6%29\"
\n" ); document.write( "\"m+=+%28-6%29%2F%28-9%29\"
\n" ); document.write( "\"m+=+2%2F3\"\r
\n" ); document.write( "\n" ); document.write( "Now use the slope formula again, only this time, use the point (n, -1) as one of the two points. The other point can be either one of the other two. Use (6, 3). Using (n, -1) and (6, 3)\r
\n" ); document.write( "\n" ); document.write( "\"m+=+%283-%28-1%29%29%2F%286-n%29\"
\n" ); document.write( "\"m+=+4%2F%286-n%29\" But \"m+=+2%2F3\", so
\n" ); document.write( "\"4%2F%286-n%29+=+2%2F3\" Multiply both sides by (6-n)
\n" ); document.write( "\"4+=+2%286-n%29%2F3\" Multiply both sides by 3.
\n" ); document.write( "\"12+=+2%286-n%29\" Divide both sides by 2.
\n" ); document.write( "\"6+=+6-n\" Subtract 6 from both sides.
\n" ); document.write( "\"0+=+-n\" or \"n+=+0\"\r
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