document.write( "Question 209825: I need help with this one. I cannot seem to understand it. I have tried for about an hour and a half and nothing is coming out of it. I am stuck. Can amyone help me solve this one?\r
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document.write( "2x/3 + 3y/4 = 11/12, x/3 + 7y/18 = 1/2
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document.write( "(solve using elimination method)\r
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document.write( "Your help is greatly appreciated.\r
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Algebra.Com's Answer #158601 by tutor_paul(519)![]() ![]() You can put this solution on YOUR website! Equation #1: 2x/3 + 3y/4 = 11/12 \n" ); document.write( "Equation #2: x/3 + 7y/18 = 1/2 \n" ); document.write( "----------------------------------- \n" ); document.write( "Multiply each and every term of Equation #2 by 2. We will call the result Equation #3. Why are we doing this? Because you will then have a 2x/3 term in each equation. Then you can subtract one equation from the other and \"eliminate\" the x term. Note that multiplying both sides of an equation by the same number does not change the equation, so it is a legal thing to do! \n" ); document.write( "Equation #3: \n" ); document.write( "------------- \n" ); document.write( "Next, subtract the newly developed Equation #3 from Equation #1: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Simplify Left side; LCD=36... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Simplify Right Side; LCD=12... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Solve for y: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------- \n" ); document.write( "Now that you have solved for y, simply substitute that value back into Equation #1 and solve for x. I will leave that part of the problem to you. \n" ); document.write( "============= \n" ); document.write( "Good Luck, \n" ); document.write( "tutor_paul@yahoo.com\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |