document.write( "Question 209825: I need help with this one. I cannot seem to understand it. I have tried for about an hour and a half and nothing is coming out of it. I am stuck. Can amyone help me solve this one?\r
\n" ); document.write( "\n" ); document.write( "2x/3 + 3y/4 = 11/12, x/3 + 7y/18 = 1/2
\n" ); document.write( "(solve using elimination method)\r
\n" ); document.write( "\n" ); document.write( "Your help is greatly appreciated.\r
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Algebra.Com's Answer #158601 by tutor_paul(519)\"\" \"About 
You can put this solution on YOUR website!
Equation #1: 2x/3 + 3y/4 = 11/12
\n" ); document.write( "Equation #2: x/3 + 7y/18 = 1/2
\n" ); document.write( "-----------------------------------
\n" ); document.write( "Multiply each and every term of Equation #2 by 2. We will call the result Equation #3. Why are we doing this? Because you will then have a 2x/3 term in each equation. Then you can subtract one equation from the other and \"eliminate\" the x term. Note that multiplying both sides of an equation by the same number does not change the equation, so it is a legal thing to do!
\n" ); document.write( "Equation #3: \"2x%2F3%2B14y%2F18=1\"
\n" ); document.write( "-------------
\n" ); document.write( "Next, subtract the newly developed Equation #3 from Equation #1:
\n" ); document.write( "\"%282x%2F3-2x%2F3%29%2B%283y%2F4-14y%2F18%29=%2811%2F12-1%29\"
\n" ); document.write( "\"2x%2F3-2x%2F3=0\" so you can rewrite the equation and solve for y:
\n" ); document.write( "\"%283y%2F4-14y%2F18%29=%2811%2F12-1%29\"
\n" ); document.write( "Simplify Left side; LCD=36...
\n" ); document.write( "\"27y%2F36-28y%2F36=%2811%2F12-1%29\"
\n" ); document.write( "\"-y%2F36=%2811%2F12-1%29\"
\n" ); document.write( "Simplify Right Side; LCD=12...
\n" ); document.write( "\"-y%2F36=%2811%2F12-12%2F12%29\"
\n" ); document.write( "\"-y%2F36=-1%2F12\"
\n" ); document.write( "Solve for y:
\n" ); document.write( "\"-y=-36%2F12\"
\n" ); document.write( "\"-y=-3\"
\n" ); document.write( "\"highlight%28y=3%29\"
\n" ); document.write( "-------------
\n" ); document.write( "Now that you have solved for y, simply substitute that value back into Equation #1 and solve for x. I will leave that part of the problem to you.
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\n" ); document.write( "Good Luck,
\n" ); document.write( "tutor_paul@yahoo.com\r
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