document.write( "Question 209787: How would I go about solving a problem such as: √27a^2b^3 I remember doing this last year, but I forgot the steps to simplifying it. \n" ); document.write( "
Algebra.Com's Answer #158576 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"sqrt%2827%2Aa%5E2%2Ab%5E3%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%289%2A3%2Aa%5E2%2Ab%5E3%29\" Factor \"27\" into \"9%2A3\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%289%2A3%2Aa%5E2%2Ab%5E2%2Ab%29\" Factor \"b%5E3\" into \"b%5E2%2Ab\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%289%29%2Asqrt%283%29%2Asqrt%28a%5E2%29%2Asqrt%28b%5E2%29%2Asqrt%28b%29\" Break up the square root using the identity \"sqrt%28A%2AB%29=sqrt%28A%29%2Asqrt%28B%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Asqrt%283%29%2Asqrt%28a%5E2%29%2Asqrt%28b%5E2%29%2Asqrt%28b%29\" Take the square root of \"9\" to get \"3\".\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Asqrt%283%29%2Aa%2Asqrt%28b%5E2%29%2Asqrt%28b%29\" Take the square root of \"a%5E2\" to get \"a\".\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Asqrt%283%29%2Aa%2Ab%2Asqrt%28b%29\" Take the square root of \"b%5E2\" to get \"b\".\r
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\n" ); document.write( "\n" ); document.write( "\"3ab%2Asqrt%283b%29\" Rearrange and multiply the terms.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"sqrt%2827%2Aa%5E2%2Ab%5E3%29\" simplifies to \"3ab%2Asqrt%283b%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"sqrt%2827%2Aa%5E2%2Ab%5E3%29=3ab%2Asqrt%283b%29\" where every variable is non-negative.
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