document.write( "Question 209704: I need help expressing the following quadratic expression in factored from by using the quadratic formula : x^2-2ax+a^2-b^2 \n" ); document.write( "
Algebra.Com's Answer #158574 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You don't need to use the quadratic formula.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2-2ax%2Ba%5E2-b%5E2\" Start with the given expression.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2-2ax%2Ba%5E2\" We're going to ignore the last term (for now) and focus on factoring the first three terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Looking at the expression \"x%5E2-2ax%2Ba%5E2\", we can see that the first coefficient is \"1\", the second coefficient is \"-2\", and the last coefficient is \"1\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"1\" by the last coefficient \"1\" to get \"%281%29%281%29=1\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"1\" (the previous product) and add to the second coefficient \"-2\"?\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"1\" (the previous product).\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Factors of \"1\":\r
\n" ); document.write( "\n" ); document.write( "1\r
\n" ); document.write( "\n" ); document.write( "-1\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"1\".\r
\n" ); document.write( "\n" ); document.write( "1*1 = 1
\n" ); document.write( "(-1)*(-1) = 1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"-2\":\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "
First NumberSecond NumberSum
111+1=2
-1-1-1+(-1)=-2
\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"-1\" and \"-1\" add to \"-2\" (the middle coefficient).\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the two numbers \"-1\" and \"-1\" both multiply to \"1\" and add to \"-2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"-2ax\" with \"-ax-ax\". Remember, \"-1\" and \"-1\" add to \"-2\". So this shows us that \"-ax-ax=-2ax\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bhighlight%28-ax-ax%29%2Ba%5E2\" Replace the second term \"-2ax\" with \"-ax-ax\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-ax%29%2B%28-ax%2Ba%5E2%29\" Group the terms into two pairs.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%28x-a%29%2B%28-ax%2Ba%5E2%29\" Factor out the GCF \"x\" from the first group.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%28x-a%29-a%28x-a%29\" Factor out the GCF \"-a\" from the second group.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x-a%29%28x-a%29\" Combine like terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x-a%29%5E2\" Condense.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"x%5E2-2ax%2Ba%5E2\" factors to \"%28x-a%29%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "----------------------------------\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"x%5E2-2ax%2Ba%5E2-b%5E2\" becomes \"%28x-a%29%5E2-b%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Notice how we have a difference of squares \"A%5E2-B%5E2\" where in this case \"A=x-a\" and \"B=b\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So let's use the difference of squares formula \"A%5E2-B%5E2=%28A%2BB%29%28A-B%29\" to factor the expression:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"A%5E2-B%5E2=%28A%2BB%29%28A-B%29\" Start with the difference of squares formula.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x-a%29%5E2-b%5E2=%28x-a%2Bb%29%28x-a-b%29\" Plug in \"A=x-a\" and \"B=b\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So this shows us that \"%28x-a%29%5E2-b%5E2\" factors to \"%28x-a%2Bb%29%28x-a-b%29\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In other words \"%28x-a%29%5E2-b%5E2=%28x-a%2Bb%29%28x-a-b%29\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "============================================================\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"x%5E2-2ax%2Ba%5E2-b%5E2\" completely factors to \"%28x-a%2Bb%29%28x-a-b%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In other words, \"x%5E2-2ax%2Ba%5E2-b%5E2=%28x-a%2Bb%29%28x-a-b%29\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );