document.write( "Question 209776: The perimeter of a rectangular building is 234 feet. The width is 25 feet shorter than the length. What are the dimensions? (Let W represent the width and L represent the length.) Is the answer A,B,C, or D? I couldn't figure it out. Thank you.\r
\n" ); document.write( "\n" ); document.write( "A) W = L - 25, 2L + 2W = 234
\n" ); document.write( "B) W = L - 25, L + W = 234
\n" ); document.write( "C) L = W - 25, 2L + W = 234
\n" ); document.write( "D) W = L + 25, 2L + 2W = 234
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Algebra.Com's Answer #158573 by jim_thompson5910(35256)\"\" \"About 
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Since \"The width is 25 feet shorter than the length\", this means that the width W is \"W=L-25\". In other words, take the length L and subtract 25 ft to get the width.\r
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\n" ); document.write( "\n" ); document.write( "Ex: if the length is 50 ft, then the width is \"W=50-25=25\" ft\r
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\n" ); document.write( "\n" ); document.write( "Now it helps to remember that the perimeter formula is \"P=2W%2B2L\" which you could rearrange to \"2L%2B2W=P\" (as the answer choices do so). Now plug in the perimeter \"P=234\" to get \"2L%2B2W=234\"\r
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\n" ); document.write( "\n" ); document.write( "Putting this together, we have the equations: \"W=L-25\" and \"2L%2B2W=234\".\r
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\n" ); document.write( "\n" ); document.write( "So the answer is A)\r
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\n" ); document.write( "\n" ); document.write( "Note: to find W and L, simply use substitution or elimination on the two equations.
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