document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209762>Question 209762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Translate the problem situation to a system of equations. Do not attempt to solve.\r<BR>\n" );
document.write( "\n" );
document.write( "The perimeter of a rectangular building is 234 feet. The width is 25 feet shorter than the length. What are the dimensions? (Let W represent the width and L represent the length.) \r<BR>\n" );
document.write( "\n" );
document.write( "A) W = L - 25, 2L + 2W = 234<BR>\n" );
document.write( "B) W = L - 25, L + W = 234<BR>\n" );
document.write( "C) L = W - 25, 2L + W = 234<BR>\n" );
document.write( "D) W = L + 25, 2L + 2W = 234  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158562 by </B><A HREF=/tutors/aboutme.mpl?userid=314><B>314(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=314><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158562\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2( W+L); W=L-25<BR>\n" );
document.write( "234=2(L-25+L) we divide with 2 (both sides of the equation)<BR>\n" );
document.write( "117=2L+25<BR>\n" );
document.write( "2L=117-25<BR>\n" );
document.write( "2L=92 we divide with 2<BR>\n" );
document.write( "L=46 feet<BR>\n" );
document.write( "W=L-25=46-25=21 feet </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );