document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29003>Question 29003</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the shorter diagonal of rhombus is equal to one of its sides. the length of a side of the rhombus is 6cm.\r<BR>\n" );
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document.write( "(a) find each diagonal of the rhombus. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15856 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15856\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> IN A RHOMBUS IF SIDE IS X WE HAVE <BR>\n" );
document.write( "(D1/2)^2+(D2/2)^2=X^2...WHERE D1 AND D2 ARE DIAGONALS<BR>\n" );
document.write( "IF D1=X THEN<BR>\n" );
document.write( "(X/2)^2+(D2/2)^2=X^2...<BR>\n" );
document.write( "(D2/2)^2=3X^2/4<BR>\n" );
document.write( "D2/2=X*SQRT3/2<BR>\n" );
document.write( "D2=X*SQRT3<BR>\n" );
document.write( "SO EACH DIAGONAL IS X AND X*SQRT(3)\r<BR>\n" );
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document.write( "NOW X=6 SO <BR>\n" );
document.write( "D1=6 AND D2 =6SQRT(3)=10.4 </SPAN>\n" );
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