document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209710>Question 209710</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you figure a rectangle with a perimeter of 70 feet and the length-to-width ratio of 3 to 4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158547 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter  =  2*Length +2*Width =70<BR>\n" );
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document.write( "but  L/W=3/4,,,or  L=(3/4)(W),,,,,subst<BR>\n" );
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document.write( "2{(3/4)W} +2W =70<BR>\n" );
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document.write( "1.5 W +2W = 70<BR>\n" );
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document.write( "3.5 W =70<BR>\n" );
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document.write( "W=20,,,,,,and  L=(3/4)20 =15<BR>\n" );
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document.write( "checking,,,2(15) +2(20) = 70,,,,ok<BR>\n" );
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