document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209698>Question 209698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bill can row 3 mph in still water. It takes him 3 hours 36 minutes to go 3 miles upstream and return. Find the speed of the current. \r<BR>\n" );
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document.write( "I've gone over and over trying this problem different ways.  I've converted the time into 216 minutes and still can't figure out what I'm doing wrong.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158539 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158539\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Bill can row 3 mph in still water. It takes him 3 hours 36 minutes to go 3 miles upstream and return. Find the speed of the current. <BR>\n" );
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document.write( "current speed = c<BR>\n" );
document.write( "d = rt = 3 miles<BR>\n" );
document.write( "t = 3/r<BR>\n" );
document.write( "3.6 = 3/(3+c) + 3/(3-c)<BR>\n" );
document.write( "3.6(3+c)*(3-c) = 3(3-c) + 3(3+c)<BR>\n" );
document.write( "1.2(9 - c^2) = 3-c + 3+c = 6<BR>\n" );
document.write( "9 - c^2 = 5<BR>\n" );
document.write( "c^2 = 4<BR>\n" );
document.write( "c = 2 mph<BR>\n" );
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document.write( "It takes 3 hour upstream at 1 mph ground speed, and<BR>\n" );
document.write( "0.6 hours downdstream at 5 mph. </SPAN>\n" );
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