document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209688>Question 209688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> you and a friend share the driving on a 300 mile road trip. your friend drives for 3 hours at an average speed of 52mph. its not your turn. how fast must you drive for the remainder of the trip if your want to reach your hotel in 3 more hours?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158527 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158527\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you and a friend share the driving on a 300 mile road trip. your friend drives for 3 hours at an average speed of 52mph. its now your turn. how fast must you drive for the remainder of the trip if you want to reach your hotel in 3 more hours? <BR>\n" );
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document.write( "1st 3 hr. DATA:<BR>\n" );
document.write( "distance = rt = 52*3 = 156 miles<BR>\n" );
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document.write( "Distance remaining: 300-156 = 144 miles<BR>\n" );
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document.write( "Rate to drive 144 miles in 3 hrs.<BR>\n" );
document.write( "144/3 = 48 mph<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "Reply to stanbon@comcast.net </SPAN>\n" );
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