document.write( "Question 209683: Story problems always confuse me. I have tried and tried to get this one, and I can't do it. Can some one please help me?\r
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\n" ); document.write( "\n" ); document.write( "The 1990 life expectancy of males in a certain country was 71.3 years. In 1995, it was 74.5 years. Let E represent the life expectancy in year t and let t represent the number of years since 1990.\r
\n" ); document.write( "\n" ); document.write( "The linear function E(t) that fits the data is\r
\n" ); document.write( "\n" ); document.write( "E(t) = ___t + ___ (round to the nearest tenth)\r
\n" ); document.write( "\n" ); document.write( "Use the function to predict the life expectancy in males in 2006\r
\n" ); document.write( "\n" ); document.write( "E(16) = ____ (round to the nearest tenth)
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Algebra.Com's Answer #158522 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The 1990 life expectancy of males in a certain country was 71.3 years. In 1995, it was 74.5 years. Let E represent the life expectancy in year t and let t represent the number of years since 1990.
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\n" ); document.write( "You have two points relating year and life expectancy: (0,71.3)and(5,74.5)
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\n" ); document.write( "slope = (74.5-71.3)/(5-0) = 3.2/5 = 0.64
\n" ); document.write( "intercept: when t = 0, expected life = 71.3
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\n" ); document.write( "The linear function E(t) that fits the data is
\n" ); document.write( "E(t) = 0.64t + 71.3 (round to the nearest tenth)
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\n" ); document.write( "Use the function to predict the life expectancy in males in 2006
\n" ); document.write( "E(16) = 0.64*16 + 71.3 (round to the nearest tenth)
\n" ); document.write( "E(16) = 81.54 yrs.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "Reply to stanbon@comcast.net
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