document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209635>Question 209635</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There is a two-digit number such that the sum of its digits is 6, while the product of the digits is 1/3 the original number. Find this number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158511 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158511\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=6 <BR>\n" );
document.write( "x=6-y<BR>\n" );
document.write( "xy=(10x+y)/3<BR>\n" );
document.write( "(6-y)y=(10[6-y]+y)/3<BR>\n" );
document.write( "6y-y^2=(60-10y+y)/3<BR>\n" );
document.write( "3(6y-y^2)=60-9y<BR>\n" );
document.write( "18y-3y^2=60-9y<BR>\n" );
document.write( "-3y^2+18y+9y-60=0<BR>\n" );
document.write( "-3y^2+27y-60=0<BR>\n" );
document.write( "-3(y^2-9y+20)=0<BR>\n" );
document.write( "-3(y-4)(y-5)=0<BR>\n" );
document.write( "y-4=0<BR>\n" );
document.write( "y=4 ans.<BR>\n" );
document.write( "x=6-4<BR>\n" );
document.write( "x=2 ans (24)<BR>\n" );
document.write( "y-5=0<BR>\n" );
document.write( "y=5 ans.<BR>\n" );
document.write( "x=6-5<BR>\n" );
document.write( "x=1 ans (15) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );