document.write( "Question 209651: I have no idea how to solve this. I am probably making it harder then it is. Can someone please help me?\r
\n" ); document.write( "\n" ); document.write( "Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 125 miles per hour. Train A passes a station at 12.25 P.M. If train B passes the same station at 12:37, at what time will train B catch up to train A? ______?
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Algebra.Com's Answer #158505 by ankor@dixie-net.com(22740)\"\" \"About 
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Trains A and B are traveling in the same direction on parallel tracks.
\n" ); document.write( " Train A is traveling at 100 miles per hour and train B is traveling at 125 miles per hour.
\n" ); document.write( "Train A passes a station at 12.25 P.M. If train B passes the same station at 12:37,
\n" ); document.write( "at what time will train B catch up to train A? ______?
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\n" ); document.write( "from the given information, we know that train B is 12 min (.2 hr) behind
\n" ); document.write( " train A, when train A passes the station
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\n" ); document.write( "The distance between the trains at this time: .2 * 125 = 25 mi
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\n" ); document.write( "Let t = time required for train B to catch train A
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\n" ); document.write( "write a distance equation: Dist = speed * time
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\n" ); document.write( "Train B travel dist = Train A travel dist + 25 mi
\n" ); document.write( "125t = 100t + 25
\n" ); document.write( "125t - 100t = 25
\n" ); document.write( "t = \"25%2F25\"
\n" ); document.write( "t = 1 hr
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\n" ); document.write( "12:25 + 1 = 1:25 pm, B catches A
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\n" ); document.write( "Check solution by finding the distances (train B travels 25 mi more than train A)
\n" ); document.write( "125 * 1 = 125 mi
\n" ); document.write( "100 * 1 = 100 mi
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\n" ); document.write( "difference = 25 mi
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