document.write( "Question 209651: I have no idea how to solve this. I am probably making it harder then it is. Can someone please help me?\r
\n" ); document.write( "\n" ); document.write( "Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 125 miles per hour. Train A passes a station at 12.25 P.M. If train B passes the same station at 12:37, at what time will train B catch up to train A? ______?
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Algebra.Com's Answer #158504 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
D=RT
\n" ); document.write( "THE DISTANCES WILL BE THE SAME. THEREFORE:
\n" ); document.write( "Da=100T
\n" ); document.write( "Db=125(T-.2)
\n" ); document.write( "100T=125(T-.2)
\n" ); document.write( "100T=125T-25
\n" ); document.write( "100T-125T=-25
\n" ); document.write( "25T=-25
\n" ); document.write( "T=-25/-25
\n" ); document.write( "T=1 HOUR IS THE TIME FOR TRAIN b TO CATHCH TRAIN a.
\n" ); document.write( "PROOF:
\n" ); document.write( "100*1=125(1-.2)
\n" ); document.write( "100=125*.8
\n" ); document.write( "100=100
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