document.write( "Question 29018: I have to do some problems like these two. Can anyone help me threw the steps on both of these so that I know how to do them.\r
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document.write( "example 1\r
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document.write( "Solve the system.
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document.write( " x + y = 9
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document.write( " x – y = 3\r
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document.write( "Example 2\r
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document.write( "Solve the system by addition.
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document.write( " –4x + 5y = 1
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document.write( " x – 4y = 19\r
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Algebra.Com's Answer #15850 by wuwei96815(245)![]() ![]() ![]() You can put this solution on YOUR website! These types of problems are best solve using elimination and substitution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In the elimination part we have to eliminate one of the varibles so that we can solve for the other. When we add x+y=9 and x-y=3, we get 2x =12. What happened to the y's? They were eliminated (y-y=0). Now you can easily solve for x. \n" ); document.write( "2x = 12 \n" ); document.write( "x = 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since we have the value of one of the variables, we can use substituion to find the other. \n" ); document.write( "x+y=9 \n" ); document.write( "(6)+ y = 9 \n" ); document.write( "y=9+6 = 15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The second problem is more difficult because simply adding the equations together will not eliminate either variable. In the second problem try multiplying the second equation by 4 and then proceeding. Let me know how you make out. \n" ); document.write( " |