document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29019>Question 29019</A>: <I><SPAN STYLE=\"word-break: break-all;\">  I have came to this. The sum of two numbers is 82.  The second is 6 more than 3 times the first.  What are the two numbers?\r<BR>\n" );
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document.write( "I got loat when I got to this point can anyone help me </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15849 by </B><A HREF=/tutors/aboutme.mpl?userid=wuwei96815><B>wuwei96815(245)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wuwei96815><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=the first number<BR>\n" );
document.write( "Then 3x+6=the second number\r<BR>\n" );
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document.write( "x + (3x+6) = 82<BR>\n" );
document.write( "x + 3x +6 = 82<BR>\n" );
document.write( "4x = 82 - 6 = 76<BR>\n" );
document.write( "4x = 76<BR>\n" );
document.write( "x = 76/4 = 19\r<BR>\n" );
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document.write( "3x+6 = 63\r<BR>\n" );
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document.write( "We know we are right because 19 and 63 = 82.  Doesn't it?  </SPAN>\n" );
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