document.write( "Question 29020: Lets say that a consultant traveled 4 hours to attend a meeting. The return trip took only 3 hours because the speed was 3 miles per hour faster. What was the consultant's speed each way. \n" ); document.write( "
Algebra.Com's Answer #15848 by wuwei96815(245)![]() ![]() ![]() You can put this solution on YOUR website! When you need to solve a problem that involves speed and time, you normally have to use the equation distance = speed x time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First part of trip distance = speed x 4 hours \n" ); document.write( "Second part of trip distance = (speed + 3mph) x 3 hours\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We know that the two distances are equal so we can set up the following equation: \n" ); document.write( "speed x 4 hours = (speed + 3mph) x 3 hours \n" ); document.write( "4speed = 3speed + 9 \n" ); document.write( "4speed -3speed = 9 \n" ); document.write( "speed = 9 mph\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "speed + 3 = 12 mph\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Does that look right? \n" ); document.write( " |