document.write( "Question 209562: a canned juice drink is 15% ans anouther juice is 5%
\n" ); document.write( "How many liters of each would it take to make it 10L that is 13% juice? \n" ); document.write( "
Algebra.Com's Answer #158444 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
a canned juice drink is 15% ans another juice is 5%
\n" ); document.write( "How many liters of each would it take to make it 10L that is 13% juice?
\n" ); document.write( "----------------------
\n" ); document.write( "Equations:
\n" ); document.write( "Quantity Eq: canned + other = 10L
\n" ); document.write( "Juice Eq::: 0.15c + 0.05t = 0.13*10
\n" ); document.write( "-----------------------------
\n" ); document.write( "Substitute for c (or for t) to solve:
\n" ); document.write( "0.15c + (0.05)(10-c) = 0.13*10
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "15c + 5(10-c) = 13*10
\n" ); document.write( "15c + 50 - 5c = 130
\n" ); document.write( "10c = 80
\n" ); document.write( "c = 8L (amt. of canned juice drink needed in the mixture)
\n" ); document.write( "Then \"other\" = 10-8 = 2L (amt. of 5% juice needed in the mix)
\n" ); document.write( "=============================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "Reply to stanbon@comcast.net
\n" ); document.write( "============================================= \n" ); document.write( "
\n" );