document.write( "Question 209552: Rewrite the equation y = (x+2)(4-2x) in intercept form. Then state the coordinates of the vertex.\r
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document.write( "(A) y = -2(x+2)(x-2);(0,-2)
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document.write( "(B) y = -2(x+2)(x-2);(0,0)
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document.write( "(C) y = -2(x+2)(x+2);(-4,-8)
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document.write( "(D) y = -2(x-2)(x-2);(4,-8) \n" );
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Algebra.Com's Answer #158442 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Rewrite the equation y = (x+2)(4-2x) in intercept form. Then state the coordinates of the vertex. \n" ); document.write( "-------------------- \n" ); document.write( "y = (x+2)(-2(x-2)) \n" ); document.write( "y = -2(x^2-4) \n" ); document.write( "y = -2x^2 + 8 \n" ); document.write( "-- \n" ); document.write( "Vertex occurs at x = -b/2a = 0/-4 = 0 \n" ); document.write( "f(0) = 8 \n" ); document.write( "--- \n" ); document.write( "So, vertex at (0,8) \n" ); document.write( "------------------------------ \n" ); document.write( " \n" ); document.write( "------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "Reply to stanbon@comcast.net \n" ); document.write( "========================================\r \n" ); document.write( "\n" ); document.write( "(A) y = -2(x+2)(x-2);(0,-2) \n" ); document.write( "(B) y = -2(x+2)(x-2);(0,0) \n" ); document.write( "(C) y = -2(x+2)(x+2);(-4,-8) \n" ); document.write( "(D) y = -2(x-2)(x-2);(4,-8) \n" ); document.write( " \n" ); document.write( " |