document.write( "Question 209552: Rewrite the equation y = (x+2)(4-2x) in intercept form. Then state the coordinates of the vertex.\r
\n" ); document.write( "\n" ); document.write( "(A) y = -2(x+2)(x-2);(0,-2)
\n" ); document.write( "(B) y = -2(x+2)(x-2);(0,0)
\n" ); document.write( "(C) y = -2(x+2)(x+2);(-4,-8)
\n" ); document.write( "(D) y = -2(x-2)(x-2);(4,-8)
\n" ); document.write( "

Algebra.Com's Answer #158442 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Rewrite the equation y = (x+2)(4-2x) in intercept form. Then state the coordinates of the vertex.
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\n" ); document.write( "y = (x+2)(-2(x-2))
\n" ); document.write( "y = -2(x^2-4)
\n" ); document.write( "y = -2x^2 + 8
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\n" ); document.write( "Vertex occurs at x = -b/2a = 0/-4 = 0
\n" ); document.write( "f(0) = 8
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\n" ); document.write( "So, vertex at (0,8)
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\n" ); document.write( "\"graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C%28x%2B2%29%284-2x%29%29\"
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "Reply to stanbon@comcast.net
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\n" ); document.write( "\n" ); document.write( "(A) y = -2(x+2)(x-2);(0,-2)
\n" ); document.write( "(B) y = -2(x+2)(x-2);(0,0)
\n" ); document.write( "(C) y = -2(x+2)(x+2);(-4,-8)
\n" ); document.write( "(D) y = -2(x-2)(x-2);(4,-8)
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