document.write( "Question 209214This question is from textbook Pre-Algebra
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document.write( ": Jess has 3 more nickels than dimes for a total of $1.50. How many of each coin did he have?
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Algebra.Com's Answer #158406 by MathTherapy(10555)![]() ![]() You can put this solution on YOUR website! Jess has 3 more nickels than dimes for a total of $1.50. How many of each coin did he have?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let the amount of dimes be D\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since he has 3 more nickels than dimes, then he has (D + 3) nickels\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the coins total $1.50, then we have:\r \n" ); document.write( "\n" ); document.write( ".1D + .05(D + 3) = 1.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".1D + .05D + .15 = 1.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".15D = 1.35\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since he has 3 more nickels than dimes, then he has 9 + 3, or \n" ); document.write( " \n" ); document.write( " |