document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209512>Question 209512</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -4(3+x)+5=4(x+3).....can i get a detailed explenation of how to do this problem, i dont know if i should add 4x to each side or not after using the distributive property. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158401 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158401\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -4(3+x)+5=4(x+3)<BR>\n" );
document.write( "-12-4x+5=4x+12<BR>\n" );
document.write( "-4x-4x=12+12-5<BR>\n" );
document.write( "-8x=19<BR>\n" );
document.write( "x=19/-8<BR>\n" );
document.write( "x=-19/8 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "-4(3-19/5)+5=4(-19/8+3)<BR>\n" );
document.write( "-12+76/8+5=-76/8+12<BR>\n" );
document.write( "76/8+76/8=12+12-5<BR>\n" );
document.write( "152/8=19<BR>\n" );
document.write( "19=19 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );