document.write( "Question 209241: if f(x) = x^2 + 3x +2 then [f(x+a)- f(x)]/a =\r
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document.write( "a) 2x+a+3 b) (x+ a)^2 - x^2 c) a^2 + 2ax + 3a d) 2x + a e) 2x+3 \n" );
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Algebra.Com's Answer #158388 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! if f(x) = x^2 + 3x +2 then [f(x+a)- f(x)]/a = \n" ); document.write( "--- \n" ); document.write( "f(x+a) = (x+a)^2 + 3(x+a) +2 \n" ); document.write( "f(x+a) = x^2 +2ax + a^2 + 3x + 3a + 2 \n" ); document.write( "----------------------------------------------- \n" ); document.write( "Subtract f(x) from f(x+a) to get: \n" ); document.write( "2ax + a^2 + 3a \n" ); document.write( "----------------------- \n" ); document.write( "Divide by \"a\" to get the final answer: \n" ); document.write( "2x + 3 + a \n" ); document.write( "========================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "Reply to stanbon@comcast.net \n" ); document.write( "-------------------------------------\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "a) 2x+a+3 b) (x+ a)^2 - x^2 c) a^2 + 2ax + 3a d) 2x + a e) 2x+3 \n" ); document.write( " \n" ); document.write( " |