document.write( "Question 209401: Smith travels 45 miles going East from the center of the town and Jones travels 70 miles going West from the same point. If Jones averages 5 miles per hour more than Smith and his trip took ½ hour longer than Smith’s. How fast was each of them traveling? \n" ); document.write( "
Algebra.Com's Answer #158383 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Smith travels 45 miles going East from the center of the town and Jones travels
\n" ); document.write( "70 miles going West from the same point.
\n" ); document.write( "If Jones averages 5 miles per hour more than Smith and his trip took ½ hour
\n" ); document.write( "longer than Smith’s.
\n" ); document.write( "How fast was each of them traveling?
\n" ); document.write( ":
\n" ); document.write( "Let s = Smith's speed
\n" ); document.write( "then
\n" ); document.write( "(s+5) = Jones speed
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: Time = \"dist%2Fspeed\"
\n" ); document.write( ":
\n" ); document.write( "Jones time = Smith's time + half hour
\n" ); document.write( "\"70%2F%28s%2B5%29\" = \"45%2Fs\" + \"1%2F2\"
\n" ); document.write( "Multiply equation by 2s(s+5), results
\n" ); document.write( "2s(70) = 45(2(s+5)) + s(s+5)
\n" ); document.write( ":
\n" ); document.write( "140s = 90s + 450 + s^2 + 5s
\n" ); document.write( ":
\n" ); document.write( "Arrange as a quadratic equation
\n" ); document.write( "0 = -140s + 90s + 5s + 450 + s^2
\n" ); document.write( ":
\n" ); document.write( "s^2 - 45s + 450 = 0
\n" ); document.write( ":
\n" ); document.write( "Factors to
\n" ); document.write( "(s-30)(s-15) = 0
\n" ); document.write( ":
\n" ); document.write( "Two valid solutions
\n" ); document.write( "s = 30 mph
\n" ); document.write( "s = 15 mph
\n" ); document.write( ":
\n" ); document.write( ";
\n" ); document.write( "Check solution using 15 mph
\n" ); document.write( "\"70%2F20\" = \"45%2F15\" + \"1%2F2\"
\n" ); document.write( "3.5 = 3 + .5
\n" ); document.write( ":
\n" ); document.write( "You can check it using s = 30 mph
\n" ); document.write( "
\n" ); document.write( "
\n" );