document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209408>Question 209408</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how is this problem factored.\r<BR>\n" );
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document.write( "  3xy^2+11xy-20x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158340 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158340\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3xy^2 +11xy -20x,,,,if  we  factor  common  term (x)<BR>\n" );
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document.write( "x(3y^2 +11y-20)<BR>\n" );
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document.write( "looking  at  second  factor<BR>\n" );
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document.write( "last  term  is  (-), therefore  factors  have  different  signs, and second  term  is  difference  of  factors<BR>\n" );
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document.write( "Middle  term  is  (+),  therefore,  largest  factor  is  (+)<BR>\n" );
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document.write( "factor  of  1st  term  is,,,  1*3<BR>\n" );
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document.write( "factors  of  last  term  are,,,1*20,,2*10,,,4*5<BR>\n" );
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document.write( "x(3y-4)(y+5),,,,,answer<BR>\n" );
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document.write( "check  by  multiplying  factors<BR>\n" );
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document.write( "(3xy -4x)(y+5) <BR>\n" );
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document.write( "3xy^2 +15xy -4xy -20x<BR>\n" );
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document.write( "3xy^2 +11xy -20x,,,,,,,ok<BR>\n" );
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