document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209413>Question 209413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in need of help with this problem (factoring)\r<BR>\n" );
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document.write( "  x^2+16x+64 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158335 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158335\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2 +16x +64<BR>\n" );
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document.write( "Sign  of  last  term  is  (+),  therefore  factors  are  the  same,  and  add  (to 16)<BR>\n" );
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document.write( "Sign  of  second  term  is  (+), therefore factors  are  (+)<BR>\n" );
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document.write( "factors  of  1st  term  are  just  1*1<BR>\n" );
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document.write( "factors  of  last  term  can be; 1*64,2*32,4*16,8*8<BR>\n" );
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document.write( "Since  they  must  add  to  16,  lets  try  8*8,,,(8+8=16)<BR>\n" );
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document.write( "(x+8)(x+8)<BR>\n" );
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document.write( "check  by  FOIL,,x^2 +8x+8x+64= x^2 +16x +64,,,,,ok<BR>\n" );
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document.write( " </SPAN>\n" );
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