document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209382>Question 209382</A>: <I><SPAN STYLE=\"word-break: break-all;\"> graph the line please<BR>\n" );
document.write( "2x - 3y = -6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158319 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> to graph the line, you need to solve for y.<BR>\n" );
document.write( "2x-3y = -6<BR>\n" );
document.write( "add 3y to both sides of the equation and add -6 to both sides of the equation to get:<BR>\n" );
document.write( "2x + 6 = 3y<BR>\n" );
document.write( "divide both sides of the equation by 3 to get<BR>\n" );
document.write( "y = (2/3)*x + 2<BR>\n" );
document.write( "now it's in a form that you can graph it with.<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "graph of y = (2/3)*x + 2 is shown below:<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C%282%2F3%29%2Ax+%2B+2%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C%282%2F3%29%2Ax+%2B+2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );