document.write( "Question 209260: A photograph measures 8 in. by 10 in. Earl put it in a frame that is 2 in. wide. Find the area of the frame and its outside perimeter.
\n" ); document.write( "Unknown: length of frame
\n" ); document.write( "Known: width of frame
\n" ); document.write( " photo is 8 in. x 10 in.
\n" ); document.write( "A=lw
\n" ); document.write( "a=l x 2 in.
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Algebra.Com's Answer #158291 by rfer(16322)\"\" \"About 
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I assume you want the area of the frame less the area of the picture?
\n" ); document.write( "(8+2)(10+2)-(8*10)=40q in of frame
\n" ); document.write( "------------------
\n" ); document.write( "P=2w+2l
\n" ); document.write( "P=2(12)+2(10)
\n" ); document.write( "P=44 in outside perimeter
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