document.write( "Question 28969: use completing the square to find the vertex of the quadratic function
\n" ); document.write( "y=-2x^2+16x+4\r
\n" ); document.write( "\n" ); document.write( "This is what i tried
\n" ); document.write( "y=-2(x^2-8x)+ 4
\n" ); document.write( "Y= -2(x-4)^2 +16-16+4
\n" ); document.write( "Y=-2(x-4)^2-12
\n" ); document.write( "vertex= (-4,-12) the answer is supposed to be vertex= (4,36)
\n" ); document.write( "Thanks for the help in advance
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Algebra.Com's Answer #15828 by sdmmadam@yahoo.com(530)\"\" \"About 
You can put this solution on YOUR website!
use completing the square to find the vertex of the quadratic function
\n" ); document.write( "y=-2x^2+16x+4
\n" ); document.write( "This is what i tried\r
\n" ); document.write( "\n" ); document.write( "y=-2x^2+16x+4
\n" ); document.write( "y =-2[x^2-8x-2]
\n" ); document.write( "y = -2{[(x-4)^2-16] -2}
\n" ); document.write( "(perfecting the square for which we needed 16 and hence added and subtracted 16)
\n" ); document.write( "y = -2{(x-4)^2-18)
\n" ); document.write( "y = -2(x-4)^2 +36
\n" ); document.write( "(y-36) = -2(x-4)^2
\n" ); document.write( "(-1/2)(y-36)= (x-4)^2 (multiplying by (-1/2) )
\n" ); document.write( "That is (x-4)^2= -4(1/8)(y-36)
\n" ); document.write( "which is of the form (x-h)^2 = -4a(y-k)
\n" ); document.write( "Square in x and linear in y represents a parabola with axis vertical
\n" ); document.write( "and since the coefficient of y is negative,the parabola looks downwards (that is the union symbol inverted)
\n" ); document.write( "Vertex = A(h,k) = (4,36)
\n" ); document.write( "a = distance of the focus from the vertex
\n" ); document.write( "=(1/8)
\n" ); document.write( "That is the focus is the point S(4,36-1/8) = S(4,287/8) which is a point
\n" ); document.write( "on the line of symmetry, x=4
\n" ); document.write( "and (1/8) unit below the vetex
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