document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209361>Question 209361</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE LENGTH OF A RECTANGLE IS TWICE ITS WIDTH. IF THE PERIMETER OF THE RECTANGLE IS 48 YARDS, FIND THE AREA </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158259 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158259\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE LENGTH OF A RECTANGLE IS TWICE ITS WIDTH. IF THE PERIMETER OF THE RECTANGLE IS 48 YARDS, FIND THE AREA<BR>\n" );
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document.write( "Let width = W.<BR>\n" );
document.write( "The length = L = 2W<BR>\n" );
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document.write( "Solve for L and W:<BR>\n" );
document.write( "Perimeter = 2(L+W)<BR>\n" );
document.write( "48 = 2(2W+W)<BR>\n" );
document.write( "6W = 48<BR>\n" );
document.write( "W = 8 yds<BR>\n" );
document.write( "L = 16 yds<BR>\n" );
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document.write( "Area = 8*16 = 128 sq. yds.<BR>\n" );
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document.write( " </SPAN>\n" );
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