document.write( "Question 209345: Please help me find the distance between the pionts (8,3) and (2,7). \n" ); document.write( "
Algebra.Com's Answer #158248 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Note: is the first point . So this means that \"x%5B1%5D=8\" and \"y%5B1%5D=3\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=2\" and \"y%5B2%5D=7\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" Start with the distance formula.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%288-2%29%5E2%2B%283-7%29%5E2%29\" Plug in \"x%5B1%5D=8\", \"x%5B2%5D=2\", \"y%5B1%5D=3\", and \"y%5B2%5D=7\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%286%29%5E2%2B%283-7%29%5E2%29\" Subtract \"2\" from \"8\" to get \"6\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%286%29%5E2%2B%28-4%29%5E2%29\" Subtract \"7\" from \"3\" to get \"-4\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2836%2B%28-4%29%5E2%29\" Square \"6\" to get \"36\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2836%2B16%29\" Square \"-4\" to get \"16\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2852%29\" Add \"36\" to \"16\" to get \"52\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"d=2%2Asqrt%2813%29\" Simplify the square root.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So our answer is \"d=2%2Asqrt%2813%29\" \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Which approximates to \"d=7.211\" \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the distance between the two points is approximately 7.211 units. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );